Re: gui in fonction
- From: Olaf Frączyk <olaf cbk poznan pl>
- To: Axel <axel azerty netcourrier com>
- Cc: gtk-app-devel-list gnome org
- Subject: Re: gui in fonction
- Date: 18 Mar 2003 12:18:44 +0100
On Tue, 2003-03-18 at 11:30, Axel wrote:
hi
I have a problem with fonction.
basically, i d like to use fonction to build my gui, so here is the function I d like to use
void create_window(GtkWidget *window)
{
window=gtk_window_new (GTK_WINDOW_TOPLEVEL);
gtk_widget_set_size_request(GTK_WIDGET(window),500,250);
}
I call it in main() as following :
GtkWidget *window;
create_window(window);
gtk_widget_show(window);
the problem is that my program segfault.
No problem when I use gtk_window_new et set_size in the main().
So is it possible to build a gui in an external function ? Where is my error ?
Hi,
It has nothing with GUI.
You just change a pointer inside function, not a value it is pointing
to.
This will not work as you expected.
Regards,
Olaf
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